(18+7k)^((1)/(2))=k

Solution for (18+7k)^((1)/(2))=k equation:

(18+7k)^((1)/(2))=k

We move all terms to the left:

(18+7k)^((1)/(2))-(k)=0

We add all the numbers together, and all the variables

(7k+18)^(+1/2)-k=0

We add all the numbers together, and all the variables

-1k+(7k+18)^(+1/2)=0

We multiply all the terms by the denominator


-1k*2)+(7k+1+18)^(=0

We add all the numbers together, and all the variables

-1k*2)+(7k+19)^(=0

We add all the numbers together, and all the variables

-1k*2)+(7k=0

Wy multiply elements

-2k^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{-4}=0$